| $4$ | Trivial | For the cube $B_\infty^n=[-1,1]^n$ one has $\mathrm{Vol}(B_\infty^n)=2^n$ and $\mathrm{Vol}\big((B_\infty^n)^\circ\big)=2^n/n!$, hence $M(B_\infty^n)=4^n$ and $C_{25}\le 4$. Conjecturally, this is sharp (Mahler conjecture). |tracked since 2026-07-24 — no movement seen yet
Lower bound, last-listed row
| $\pi \approx 3.1416$ | [K2008] | Best known explicit constant to date (Kuperberg). |tracked since 2026-07-24 — no movement seen yet
Cite this rowBounds Ledger — Mahler volume product constant (25a)
upper bound: $4$ (tracked since 2026-07-24 — no movement seen yet)
lower bound: $\pi \approx 3.1416$ (tracked since 2026-07-24 — no movement seen yet)
Mirrored from teorth/optimizationproblems@2c1968c. These are the last-listed rows of that constant's bounds table — a listing position, not a statement that this bound is the strongest or most recent. A snapshot at that sha, not a live read.
https://u00dxk2.github.io/bounds-ledger/c/25a.html